I have a clinder full of oil with 4000N presing down on it between the weight and oil ther is 0.02^2


what is the presure of the oil in Pa?

Originally posted by Chief yelling alot
I have a clinder full of oil with 4000N presing down on it between the weight and oil ther is 0.02^2


what is the presure of the oil in Pa?

42

You're in Canadada, why do you want to know what the pressure would be in Pennsylvania?

Originally posted by Chief yelling alot
I have a clinder full of oil with 4000N presing down on it between the weight and oil ther is 0.02^2


what is the presure of the oil in Pa?

WTF are you talking about

pressure = Force/Area

wtf is 0.02^2????????


Speak english mother fucker

here, let me help you out (cause i am sure you would spell it wrong) (http://www.hop.com/index.jhtml;jsessionid=KAXTDFZJ4ZNKZQFIZBSCFEWAVDE MQIV0?flashTest=true)

pressure in a liquid is distributed equally throughout... whats the .o2^2... is that viscosity? can u write the whole quesiton word for word

Originally posted by TRD




wtf is 0.02^2????????




.02 squard


ya fuck :flipoff:

oh wait Pa= pascals # thing... right? soome kinda conversion that i dont remember. sorry dude

Originally posted by Chief yelling alot


.02 squard


ya fuck :flipoff:

No WTF does it refer to Ya Canuk :flipoff2:

Originally posted by fRED dURST


42



thats wrong :(


I have a pic of the question + diagram if someone is willing to post it

im it to me - is this a fluids problem or a math problem?

Originally posted by Chief yelling alot


thats wrong :(


I have a pic of the question + diagram if someone is willing to post it

email it to motorhead72k5@msn.com

Originally posted by Chief yelling alot
I have a clinder full of oil with 4000N presing down on it between the weight and oil ther is 0.02^2


what is the presure of the oil in Pa?

I'm not sure what you're trying to calculate with those numbers, but use this to figure out what your trying to acheive:

calculate the area of the internals of your vessel and then dived that into the wieght/force applied on top.

You've also have to consider at what point are you measuring the pressure. If your measuring at the top, then the pressure will be less than it is at the bottom.

Also, you can apply pressure at the bottom and your pressure will not be as high at the top as it is at the bottom.

Originally posted by fRED dURST


email it to motorhead72k5@msn.com

sent


montypics is down

the answer is 200,000N/m^2 assuming .02 is really .02m^2

Originally posted by TRD
the answer is 200,000 assuming .02 is really .02m^2


how did you get that :eek:

Can't help with the math, but I can help with the spelling.......

Hydrolic = Hydraulic ;) :flipoff2:

Originally posted by Chief yelling alot



how did you get that :eek:

It is Force divided by area. So i assumed that your force is 4000N (as given) and the area is .02 meters squared. Simply divide.

ok, here it is.

no to be a jerk, but that seems to be a simple plug and chug as it is written

Originally posted by fRED dURST
ok, here it is.


thanks


hmmm so simple

I never tryed the F/A thought ide get a smaller number :rolleyes:

that .02m^2 is the area of the face of the cylinder where the force is being applied, not an area between the piston and cylinder (otherwise it would be m^3)

this college or HS stuff?

TRD's got it right.

F = PA can be rearranged as P = F/A

Therefore:

4000N / .02 m^2 = 200000 N/m^2

a N/m^2 is equal to a pascal so again can be rewritten as:

200000 Pa or 200 kPa

Originally posted by mobil1syn
this college or HS stuff?

Institute of Technology

thanks so much guys, I was beating my head over that one :eek:

i thought Pa meant pascals... anyway when u got problems like that try to think of the problem in another way... think of standing on a beer can and then use the equation they gave u to figure out how much pressure is on the beer can. then youll at least be more interested and in my experience, put forth a lil more time+effort