: Shackle angle geometry.


YJ_WOLF95
10-06-2004, 11:59 PM
If you know the 3 lengths of a triangle, how do you figure out the angles on the 3 corners? Like a triangle that is 49"x52"x4"? Also a triangle of 49"x52"x5.5"?

Ive got my springs mounted and they are 52" long and the mounting bolts are 49" bolt to bolt, and the spring and hanger are 4" apart right now. Trying to figure out the angle the shackle is sitting at.

And help you guys can give me would be great!

LilGnt
10-07-2004, 01:15 AM
The law of cosines can be used to find an angle when you know three sides of a triangle.

Solving for a given angle you'll want to use the form

A = arccos[(b^2+c^2-a^2)/(2bc)]
where a, b, and c are the lengths of the triangle and A is the angle across from a (as in between b and c).

So a 49, 52, 4 triangle has small angle of 3 degrees.

YJ_WOLF95
10-07-2004, 11:54 AM
Hey thanks for the formula. I dont have a calculator with me, so could you tell me the other two angles as well? If the small angle is 3 degres, what is the acute angle, and the obtuse angle in the triangle?