hey, i saw a post on here a month or so ago...i searched for it with no luck. someone had an equation of how the figure out your lock to lock turns...it was sumthing like how much your valve flows dived by the bore of the ram....if anyone knows the link to that post...please let me know..thanks!

here it is all u ever wanted to know about hydro steering,, all u tech weenies go smoke some crack before u read the pdf files
all kinds of good formulassaur danfoss (http://www.sauer-danfoss.com/Literatur/index.html) :cool:

You devide the steering cylinders volume by the number of turns that you want at the steering wheel.

On a single ended cylinder you find the volume by..

The volume of the large volume side.

V= pi/4 x D^2 x S

The volume of the small volume side.

V= pi/4 x ( D^2 - d^2) x S

Volume of a double ended cylinder.

V= pi/4 x (D^2 - d^2) x S

Where:
V=volume
D=cylinder bore
d=shaft diameter
S=stroke

If you need any more help, or need help getting any hydraulic steering parts let me know.

Sean

Just to add to the last post....

With a 2" bore, 8" stroke cylinder with a 1.125" shaft. The large side of the cylinder has nearly 50% more volume than the small side. So you steering ratio is going to be about 50% slower on the large side no matter what size valve that you use.

Using a 4.8 cu.in./revolution valve , you will have 2.6 turns of the steering wheel from center to lock in one direction, and 1.8 turns in the other. Steering from lock to lock you would have 5.2 turns in one direction, and 3.6 in the other.

Again, let me know if I can help you with anything.

Sean

Station is the above true with your double ended ram ?

Originally posted by redruM
Station is the above true with your double ended ram ?

Double ended rams don't have a large side, that is why you want one. So no that doesn't happen with them.

Originally posted by Station
Just to add to the last post....

With a 2" bore, 8" stroke cylinder with a 1.125" shaft. The large side of the cylinder has nearly 50% more volume than the small side. So you steering ratio is going to be about 50% slower on the large side no matter what size valve that you use.

Using a 4.8 cu.in./revolution valve , you will have 2.6 turns of the steering wheel from center to lock in one direction, and 1.8 turns in the other. Steering from lock to lock you would have 5.2 turns in one direction, and 3.6 in the other.

Again, let me know if I can help you with anything.

Sean

The above is true when there is no resistance.

And now set the front end on the ground. Now, since the cylinder does not have as much force the same way it should be faster. The lose in power makes up for the fact that it needs less fluid. Therefore the diffrence in the two strokes(in and out) works out to be almost the same.

Originally posted by emsoffroad


The above is true when there is no resistance.

And now set the front end on the ground. Now, since the cylinder does not have as much force the same way it should be faster. The lose in power makes up for the fact that it needs less fluid. Therefore the diffrence in the two strokes(in and out) works out to be almost the same.

Nope, thats wrong. The valve puts out the same ammount of fluid per revolution despite pressure on the system.

The numbers will be the same whether there is external pressure on the steering or not, as long as the pump puts out enough fluid flow to meet the valves requirements.

Sean

Originally posted by redruM
Station is the above true with your double ended ram ?

Doube ended steering cylinders have equal volume on either side of the piston, so steering in either direction will be equal.

Sean