I am designing my flatbed and I was thinking about the size that I wanted the wheel arches to be (at the base). I'm not going to try to explain the problem that I encountered. I hope that the picture is sufficient. I know I'm being kind of anal but I am curious as to the procedure for tackling this problem. Please shw your work.


thank you

http://bbs.off-road.com/ubbthreads/download.php?Number=905377

you are about 100 IQ too smart for most of us:flipoff2:
Just kidding.........let me get out my old college book and see if I can remember this.

~33.16
since I don't really remember much from trig or calc.
I used a*2+b*2=c*2
c=18
b=7
W=2 x a
Did I cheat:D

From the looks of my ruler


4.25 inches :flipoff2: :flipoff2:

Originally posted by roverhybrids
~33.16
since I don't really remember much from trig or calc.
I used a*2+b*2=c*2
c=18
b=7
W=2 x a
Did I cheat:D

Very good......... ans= 19.31

Somethin aint right here. The hyp should be the largest measurement. It is late, am I smokin crack?? OK time for bed.

Originally posted by PIG


Very good......... ans= 19.31

Somethin aint right here. The hyp should be the largest measurement. It is late, am I smokin crack?? OK time for bed.

Yes am I am smokin crack I added where I should have subtracted ans= 16.583*2 Forgot to multipuly by 2.

come back with someting tough. :flipoff2:

Originally posted by PIG


Yes am I am smokin crack...

Damn! You're JUST too far a drive.. :D

Originally posted by liveaxle
I am designing my flatbed and I was thinking about the size that I wanted the wheel arches to be (at the base). I'm not going to try to explain the problem that I encountered. I hope that the picture is sufficient. I know I'm being kind of anal but I am curious as to the procedure for tackling this problem. Please shw your work.


thank you

http://bbs.off-road.com/ubbthreads/download.php?Number=905377

easiest way is a^2 + b^2 = c^2

where a=7
c=18
b=?

once you find out b then that will be half of the distance you are looking for..

(7^2) + b^2 = (18^2)

49 + b^2 = 324

b^2 = 275

take square root of both sides b=16.583

now 2 * b will give you the length of the line in question

so 16.583 * 2 = 33.166 <-----

there's a million ways to do this.. unit circle i would think.. trig functions.. curve formulas.. i bet this is easiest using the info you gave..

:D :D

Forget trig. Why not draw a circle on the garage floor/cardboard/plywood, get something straight thats about 3 feet long and a framing square. Probably can move the mess around in about a minute and figure it out. You won't get it to 2 decimal places though.:D

If I am reading this right you are going use 36 inch tires with your flat bed.. You need to account for the suspension flex allowing the tire to stuff up into the wheelwell.. So to start you want the wheel well to be 36 inches just for the tire diameter.. You also need a small amount of additional space around the tire to prevent rubbing(I like 2 inches on each side)..so we have 36"(tire diameter)+4"(rub prevention space)=40 inches..Next you need to offset the wheelwell to the rear slightly due to rearward movement allowed by the shackle I like to offset mine 1" to the rear which allows the axle 2 inches of rearward movement with 1 inch of rub prevention space left over..

I'm sure I could remeber the trig if I pounded my head a little, but it was quicker just to draw up your measurements in CAD and I get a distance of 33.17"

Originally posted by 4Bangler
I'm sure I could remeber the trig if I pounded my head a little, but it was quicker just to draw up your measurements in CAD and I get a distance of 33.17"


mine tooo

33.17

Roverhybrids has it right.
The red line is 33.16 inches.

Simple pythagoras, remember the tin man at the end of Oz ?
High school stuff.

18 squared = X squared plus 7 squared.
( X is half of the red line )
Solve for X ( x=16.56 )
Double that for 33.16

The answer is correct, but my Trig is a little hazy. How did you determine the hypotenuse (c) to be 18?

The radial line (radius) forms the hypotenuse. :D

Originally posted by LOPPY


Damn! You're JUST too far a drive.. :D

HA...... I guess I really was..........:flipoff2:

i don't have a calculator with me but it is 2 times the square root of 275

Heres the work. Your teacher will enjoy....

KB

what ever happened to bolt it up, flex it, cut off the shit that rubs, repeat until rubbing stops?

Originally posted by redruM



mine tooo

33.17

WTF is this trig that you speak of...?

i get 33.16624790 on my CAD.

:confused:

COOL

i think you got a close enough answer :eek:

good work fellas!!

Gee, that's good guys. I'm suprised that so many here are so well versed in math (or CAD :rolleyes:). Thanks for the help. I am not sure of the opening size that I want so its good for me to know how you guys got the answer.


thanks :D

Where the hell did my beer go?

Jeeper

Fawkin A. We got that straightened out, now, lets vote....:flipoff2: