What part of a tripled transfer case gets the most torque?

[longtrackrmk]

Is it the front planetary box or the rear transfer case that will have the most load on it when its in its lowest gear? I have a pile of 241c transfer cases 2 are the 32 spine input the other 7 are 27 spine! I have all the machine tools to make all the parts for doubling / tripling so it only cost the time to make the pieces! So should the 27 spline be in the front or back, or should I just get another 32 spine so there all the same?
Thanks for any input!

[Odin K30]

Why not just run all 9 cases so they can all spread the load?

[lumpdog]

Originally Posted by Odin K30

Why not just run all 9 cases so they can all spread the load?

That'd never work, what are you thinking??? Unless of course #7 is run in reverse to counteract the torque load, then all would be well. That and the rear planetaries would need shaved down to a 15* angle to make it handle the load. Of course the rear shafts need to be made from unobtanium, but you all already knew that.

[K5runner@hotmail.com]

No, the way you make it work is; you have the 8th case's front output go to a divorced (9th) case under the 3-4 case (depending on wheel base of course), then you can have good driveshaft angles. and don't even think about bolting them you HAVE to tig them together so they don't come apart. Then you can just run a 250cc 2 cycle motor to save weight and rev up. Don't cheep out with a Yamaha go balls out and get a Honda.

[Grumpy_old_fart]

i keep saying... 11 hp briggs and stratton is all you need...

Bolt those cases together!

[sjracer]

back in wubya wubya two them germains tried that. they actually hooked them up in a "U". it went from the rear engine to the rear bumper and back. they called a "cobbledawagen". it had a rubber driveshaft to the rear diff that was completely hinged on solid gold bushings! the crawl ratio was 22,421:1. because of this it could be powered by minature giraffes. opulence, they had it!

really why would you need more than a properly geared transfer and a doubler, with properly geared diffs. keeping whatever powerplant you are using in its powerband is more important than a sub 1 mph crawl speed.and as far as what gets the most torque it is definately the ouput shaft and the pinion on the diff. if they cant handle your multiplied torque then its not going to work anyway.

[cr480r]

Put the stronger parts in the rear.

[spidr]

Anything less than 32 forward gears is a waste of time. The 33rd forward gear is bragging rights.

Go ahead and triple it up, put the strongest parts in the back, and prepare to break a lot of shit. As in EVERYTHING.

[trkklr77]

you know what dick, just because you have 2 more gears than me doesnt give you the right to...............







ok, it does

[MochaMike]

And here I thought the IH DANs were bad.

[TGomes1987]

Whenever you gear down the shaft, you increase the torque.

For example, a 2:1 gear ratio would give you 1/2 the rotational speed, but double the torque.

So if you had three cases attached together with a 2:1 gear ratio,
that would give you 8 (NOT 6!) times the amount of torque leaving the three cases, but 1/8 of the speed.

So, as was said already, put your strongest parts at the end.

[spidr]

Originally Posted by TGomes1987

Whenever you gear down the shaft, you increase the torque.

For example, a 2:1 gear ratio would give you 1/2 the rotational speed, but double the torque.

So if you had three cases attached together with a 2:1 gear ratio,
that would give you 6 times the amount of torque leaving the three cases, but 1/6 of the speed.

So, as was said already, put your strongest parts at the end.

Before you give advice, that is obviously wrong, try to learn a little bit about the way it all works.

[enigma2y0u]

There is a subtle, but important difference between adding and multiplying.

[JOKER4X4]

Originally Posted by TGomes1987

Whenever you gear down the shaft, you increase the torque.

For example, a 2:1 gear ratio would give you 1/2 the rotational speed, but double the torque.

So if you had three cases attached together with a 2:1 gear ratio,
that would give you 6 times the amount of torque leaving the three cases, but 1/6 of the speed.

So, as was said already, put your strongest parts at the end.

Originally Posted by spidr

Before you give advice, that is obviously wrong, try to learn a little bit about the way it all works.

Originally Posted by enigma2y0u

There is a subtle, but important difference between adding and multiplying.

But spidr, you put two 4spds together, that's 8 speeds in total...

May I ask what super-light rig you are putting this triple-x-case in? The 241 in one of my Suburban's lasted 4 weekends in the bush with nothing more than 33's and a stock 350. The 241 HD's internals were turned into shrapnel in one of my old D250's (12v/getrag 5spd).

Have you considered a 203/205? Sell some 241's and you would cover the whole doubler build.

JOKER

[Grumpy_old_fart]

Originally Posted by JOKER4X4

But spidr, you put two 4spds together, that's 8 speeds in total...

May I ask what super-light rig you are putting this triple-x-case in? The 241 in one of my Suburban's lasted 4 weekends in the bush with nothing more than 33's and a stock 350. The 241 HD's internals were turned into shrapnel in one of my old D250's (12v/getrag 5spd).

Have you considered a 203/205? Sell some 241's and you would cover the whole doubler build.

JOKER

2 four speeds would give you 16 different speeds, not counting double reverse, and that would give you 17...

[MochaMike]

Originally Posted by Grumpy_old_fart

2 four speeds would give you 16 different speeds, not counting double reverse, and that would give you 17...

Not counting Reverse, you have 16 with two 4 speeds & one tcase.
Ironically you also have 16 with two (different speed) transfercases (like in my sig).


(Note: this is all Sunday morning math, so I may be wrong).

[TGomes1987]

Explain to me how that is wrong.

I was giving him the example that if three cases were in low range with a 2:1 low range ratio of each case (which they are most likely not), the final torque on the outgoing shaft would be 8 (not 6 as I said before) times that of the incoming shaft torque.

Maybe I did not explain myself correctly.

I was not saying that having more gears would automatically increase the torque, because if everything was in high range (1:1 ratio), the torque throughout would be the same.

[Filthy McChevy]

The part that breaks first. Really though, PM GeeWhiz, he'll be stoked.

[dahoyle]

Originally Posted by TGomes1987

Explain to me how that is wrong.

I was giving him the example that if three cases were in low range with a 2:1 low range ratio of each case (which they are most likely not), the final torque on the outgoing shaft would be 6 times that of the incoming shaft torque.

Maybe I did not explain myself correctly.

I was not saying that having more gears would automatically increase the torque, because if everything was in high range (1:1 ratio), the torque throughout would be the same.

For fucks sake. New to math?

2X2X2 does not equal 6. Maybe you explained yourself perfectly, but you just didn't know what the fuck you were talking about.

[spidr]

Originally Posted by MochaMike

Not counting Reverse, you have 16 with two 4 speeds & one tcase.
Ironically you also have 16 with two (different speed) transfercases (like in my sig).


(Note: this is all Sunday morning math, so I may be wrong).

4 x 4 x 2(1 t-case) = 32. Hi and low double reverse gives you 34 total. With 2 identical transmissions, you have a lot of duplicates though. It's allright, you apparently have the same issues as the next post.....

Originally Posted by TGomes1987

Explain to me how that is wrong.

I was giving him the example that if three cases were in low range with a 2:1 low range ratio of each case (which they are most likely not), the final torque on the outgoing shaft would be 6 times that of the incoming shaft torque.

Maybe I did not explain myself correctly.

I was not saying that having more gears would automatically increase the torque, because if everything was in high range (1:1 ratio), the torque throughout would be the same.

Go grab a calculator please and enter 2 x 2 x 2 and press the = key, and report back.

Originally Posted by dahoyle

For fucks sake. New to math?

2X2X2 does not equal 6. Maybe you explained yourself perfectly, but you just didn't know what the fuck you were talking about.

[trkklr77]

for the record, fuck your 34 gears including reverse's.


i have 30 forward and 6 reverse x 3 x 2

[postaldave]

divorce the third one and use the front output to run to the rear axle. best of all you can you use a front axle without having to do all those crazing mods to get the direction right.

instant free rear steer!

[TGomes1987]

Ah yes I added them instead of multiplying.

My explanation was correct, just not my terrible math skills.

I edited it on my earlier post so it is 8, not 6.

Carry on.

[mudskipper4x4]

Classic pirate awesomeness!!!

[sjracer]

2x2=4+3.1415972/8x6+ two (2) 2x4's= 842 forward speeds and 132 reverse speeds. no matter how many forward gears you have you still wont be opulent. now with mini giraff shifters hmmmm...................