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Old 10-28-2006, 09:53 AM   #1 (permalink)
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need an expert's help

I just picked up a 406 or 416 axle, and I know there are different ratios. Could some one help me figure out what ratio I have. The tag reads:
A22:7 V27:13
AU2/126-3.7
416141-902211
IV E037
Thanks in advance
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Old 10-28-2006, 10:28 AM   #2 (permalink)
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Just multiply the ratios, they are for the ring/pinion and hubs. The answer is 6.5275 (approx.).

Charlie
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Old 10-28-2006, 01:45 PM   #3 (permalink)
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What Charlie said.

The R&P is 22:7 or 3.143:1. The hub gear-set is 27:13 or 2.077:1. Overall ratio is 6.527:1 (approx).

The actual ID# is AU2/12 S-3.7

Meaning: Front axle, Unimog, series 2, version 12 (disk), with diff lock, 3.7 metric ton capacity.

Model # 737.101 or .130

Of course, all this assumes the original gears are still inside (not always 100% sure thing).
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Last edited by Discosaurus; 10-28-2006 at 01:47 PM.
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Old 10-28-2006, 05:05 PM   #4 (permalink)
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wow thanks guys it makes sense to me now. Discosaurus you said that code meant "disk" as in disc brakes right? Well this one is a drum axle. Maybe it'a an incorrect tag
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Old 10-29-2006, 07:14 AM   #5 (permalink)
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Quote:
Originally Posted by IHC4B
wow thanks guys it makes sense to me now. Discosaurus you said that code meant "disk" as in disc brakes right? Well this one is a drum axle. Maybe it'a an incorrect tag
<shrug> It wouldn't be the first time there was conflicting info in the tech data book. It says version 12 and up axles are disk. Version 11 and earlier were drums. Since you have drum brakes, maybe they made the transition somewhere during the version 12 production run ??

Only sure way to know (except by sight ) is by model #. The 737.101 and 130's were disk. 737.001 and 030 were drum.
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