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I semi-sorta agree with just makin it go as sharp as the axle will let you (or almost as sharp as it can to help save a few u-joints).

where L = length of wheelbase

and A is the angle of the line drawn from the center of the offside tire to the point where the nearside tire centerline intersects the rear axle centerline.

There's also a small correction factor I left out that has to do with tire width and caster/camber but you can add 6-12 inches to the above and be pretty close.

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567 Posts

Turning diameter = 2 * (L / sine(A))

Here are the calculations on mine.

Wheel base 101.4, track width 58.0, max turn of inside wheel 37° (I guessed on this, I'll measure tomorrow).

With those measurements, a 37° inside wheel turn means the angle for the outside wheel would be about 27° (you can get this part by sketching and using sines to factor in wheelbase and track width).

Turning diameter = 2 * (L / sine(A))

Sine of 27° is 0.454.

101.4 / .454 = 223 x 2 = 446 inches or 37 feet, which is about right for my XJ.

I don't know why that first formula was wrong, unless they're just defining how to measure angle A differently than what I used, but this one seems to work.

Now, why would anybody want to make a joke out of a serious college-level wheeling question? *I* certainly never make jokes about anything.aaronlosey said:

Yes I relize that driving in a circle is the easiest way. But I need to find out that I have enough radius before I build it:flipoff:aaronlosey said:

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